![\"Operational](\"http:\/\/72.233.35.22\/wp-content\/uploads\/2009\/03\/op-amp_symbol.png\" "\\"Operational")
These past two weeks at work have been a re-introduction to ECE 320: Electronic Devices and Controls. I have to do something that is very simple conceptually, but continually reminds me why I am not a hardware guy with how complex it actually is. <\/p>\n
The problem:<\/strong> signal = signal – 10;<\/p>\n done!<\/strong><\/p>\n In hardware this involves 4 resistors and operational amplifier and expensive 10 volt reference, two regulators and power supplies to handle the power requirements, and more capacitors than you can shake a stick at. Save me now.<\/p>\n Well, I got some help, cause we employ people who actually know how to do this stuff and he came up with some designs for me. But I had to check them out. He told me what they would do, but I had to confirm, build it, and test it. I was very impressed with myself in how much I remembered. I was able to, in the span of half an hour, figure out the whole thing, including all the intermediate steps. It was just like taking a test in college. I can now add another class to the list of classes where I learned something that I have applied directly in work. There are a lot of those by the way. Maybe OSU CSE isn’t as bad as I thought it was in school.<\/p>\n The circuit didn’t work when I tested it. Today we discovered I managed to screw up and pick the one, in stock, op amp available that is not at all what I need. It was a current feedback amplifier, whatever that is. Apparently there are more than one kind; but can’t blame the ECE department for not telling me that. I’m not supposed to have to worry about this stuff.<\/p>\n","protected":false},"excerpt":{"rendered":" These past two weeks at work have been a re-introduction to ECE 320: Electronic Devices and Controls. I have to do something that is very simple conceptually, but continually reminds me why I am not a hardware guy with how complex it actually is. The problem: I’ve got a signal that runs from 0 to […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[7,14],"tags":[],"_links":{"self":[{"href":"http:\/\/liryon.net\/index.php?rest_route=\/wp\/v2\/posts\/932"}],"collection":[{"href":"http:\/\/liryon.net\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/liryon.net\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/liryon.net\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/liryon.net\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=932"}],"version-history":[{"count":6,"href":"http:\/\/liryon.net\/index.php?rest_route=\/wp\/v2\/posts\/932\/revisions"}],"predecessor-version":[{"id":941,"href":"http:\/\/liryon.net\/index.php?rest_route=\/wp\/v2\/posts\/932\/revisions\/941"}],"wp:attachment":[{"href":"http:\/\/liryon.net\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=932"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/liryon.net\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=932"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/liryon.net\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=932"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nI’ve got a signal that runs from 0 to 18 Volts. I have an analog to digital converter board that can handle voltages from -10 to 10 volts. I need to essentially subtract 10 volts from my input signal. In C:<\/p>\n